[v = 10i]
[\frac{v_2}{6} + \frac{v_2 - v_1}{4} = 0]
[v_1 = 4 \text{ V}, v_2 = 2 \text{ V}] Problem 4.12
Find (R_{eq}):
Label the nodes and apply KCL:
[R_{eq} = 2 \parallel 4 = \frac{2 \times 4}{2 + 4} = \frac{8}{6} = \frac{4}{3} \Omega]
[i = 1 \text{ A}] Problem 3.15
Find the Thevenin equivalent circuit for the circuit of Fig. 4.78.
[30i = 30]
Applying KVL, we get:
The Thevenin equivalent circuit consists of a 12-V source in series with a (\frac{4}{3})-ohm resistor.
Solve the system of equations:
[v = 10i]
[\frac{v_2}{6} + \frac{v_2 - v_1}{4} = 0]
[v_1 = 4 \text{ V}, v_2 = 2 \text{ V}] Problem 4.12
Find (R_{eq}):
Label the nodes and apply KCL:
[R_{eq} = 2 \parallel 4 = \frac{2 \times 4}{2 + 4} = \frac{8}{6} = \frac{4}{3} \Omega]
[i = 1 \text{ A}] Problem 3.15
Find the Thevenin equivalent circuit for the circuit of Fig. 4.78.
[30i = 30]
Applying KVL, we get:
The Thevenin equivalent circuit consists of a 12-V source in series with a (\frac{4}{3})-ohm resistor.
Solve the system of equations:
