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where S_core is the reluctance of the core and S_air is the reluctance of the air gap.
S = l / (μ₀ * μr * A)
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S = MMF / Φ = 5000 / 0.5 = 10,000 A/Wb
Φ = MMF / S = 1600 / 5969 = 0.268 Wb
S = 0.5 / (4π x 10^(-7) x 1000 x 0.01) = 3980 A/Wb
The reluctance of the air gap is given by: magnetic circuits problems and solutions pdf
The magnetic flux is given by:
S = l / (μ₀ * μr * A)
S = S_core + S_air
μr = l / (μ₀ * A * S) = 1 / (4π x 10^(-7) x 0.05 x 10,000) = 1591.5
MMF = NI = 200 x 8 = 1600 A-turns
A magnetic circuit consists of a coil of 200 turns, a core with a cross-sectional area of 0.02 m², and a length of 0.8 m. The air gap length is 0.5 mm. If the current through the coil is 8 A, find the magnetic flux. where S_core is the reluctance of the core
where μ₀ is the permeability of free space and μr is the relative permeability of the core.
Assuming μr = 1000, we get: